State the units for intensity using only fundamental units? (Hint: work from #W/(m^2)#)

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Answer 1 · 2018-08-06T21:50:55

#(kg)/(s^3)#

Steps shown below:

#W/m^2= (J/s)/m^2= ((Nm)/s)/m^2= (((kgm)/s^2*m)/s)/m^2= (((kgm^2)/s^2)/s)/(m^2)=(( kgm^2)/s^3)/(m^2)= (kg)/(s^3)#

Answer 2 · 2018-08-06T22:03:10

#(kg)/s^3#
kilograms over seconds cubed

#m^2# is already in fundamental units, so let's work on #W# (which stands for power)

#W=(Fd)/t#

The fundamental unit for distance is #m# and for the time it's #s#

#F=ma#

The fundamental unit for mass is #kg# and the unit for acceleration is #m/s^2#

So, we know that #((kg*(m/s^2)*m)/s)/m^2#

Simplifying we get #(kg)/s^3#