Sue is 7 years older than Bob. Three less than twice Bob's is Sue age, find bob and Sue's ages now?
Do some algebra to figure out that
Since Sue is
Bob is 10 Sue is 17
Let s = Sue's age
Let b = Bob's age
Sue is 7 years older than Bob so Sue is:
Three less than twice Bob's age:
You need to solve these simultaneously.
Add 3 to both sides:
Subtract b from both sides:
Substitute 10 for b in equation [ 1 ]