Suppose 6.00 ml of h2 reacted with sufficient nitrogen. how many ammonia would be produced?

1 Answer
Apr 19, 2018

About #68*g# product...

Explanation:

Look at your stoichiometric equation....

#1/2N_2 + 3/2H_2(g) rarr NH_3(g)#

And this CLEARLY says that #2/3*"equiv"# with respect to ammonia is generated per equiv of dihydrogen... Here we gots #6.0*mol# dihydrogen, and so we gets #6.0*molxx2/3=4.0*mol# with respect to #NH_3#...

Note that this reaction assume #100%# yield, which is RARELY realized in ammonia synthesis...