# Suppose a ball is kicked horizontally off a mountain with an initial speed of 9.37 m/s. If the ball travels a horizontal distance of 85.0 m, how tall is the mountain?

Nov 28, 2015

$403.1 \text{m}$

#### Explanation:

First get the time of flight from the horizontal component of motion for which the velocity is constant:

$t = \frac{s}{v} = \frac{85}{9.37} = 9.07 \text{s}$

Now we can get the height using:

$h = \frac{1}{2} \text{g} {t}^{2}$

$\therefore h = 0.5 \times 9.8 \times {9.07}^{2} = 403.1 \text{m}$