Suppose #Log_b2=a# and #Log_b3=c#, how do you find #Log_b(72b)#?

1 Answer
May 10, 2016

Answer:

#log_b 72b=2c+3a+1#

Explanation:

#log_b 2=a#
#log_b 3=c#
#log_b 72b=?#

#log_b 72b=log_b 3^2*2^3*b#

#log _x ( k*l*m)=log_x k+log_x l+ log _x m#

#log_b 72b=log_b 3^2+log _b 2^3+log _b b#

#log_b=3^2=2*log_b 3=2*c#
#log _b 2^3=3*log _b 2=3*a#
#lob_b b=1#

#log_b 72b=2c+3a+1#