Suppose that 10.78 mL of 0.0512 M NaOH were required to titrate a sample of unknown acid. How many moles of NaOH were used?

1 Answer
anor277
Feb 10, 2018

#n_"NaOH"=5.52xx10^-4*mol#

Explanation:

By definition, #"concentration"="moles of solute"/"volume of solution"#

And thus for #"moles of solute"#, we take the product....

#"moles of solute"="volume of solution"xx"concentration"#

And so .................................

#n_"NaOH"=10.78*mLxx10^-3*L*mL^-1xx0.0512*mol*L^-1=??*mol#

What are (i) the mass of sodium hydroxide here, and (ii) the #pH# of this solution?

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