# Suppose that 11 inches of wire costs 44 cents. At the same rate, how much (in cents) will 28 inches of wire cost?

Aug 19, 2017

See a solution process below:

#### Explanation:

Let's call the amount the 28 inches of wire will cost: $c$

We can then write and solve for $c$:

$\left(44 \text{ cents")/(11" in") = c/(28" in}\right)$

$\textcolor{red}{28 \text{ in") xx (44" cents")/(11" in") = color(red)(28" in") xx c/(28" in}}$

color(red)(28color(black)(cancel(color(red)(" in")))) xx (44" cents")/(11color(red)(cancel(color(black)(" in")))) = cancel(color(red)(28" in")) xx c/color(red)(cancel(color(black)((28" in"))

$\frac{28 \times 44 \text{ cents}}{11} = c$

$\frac{28 \times \textcolor{red}{\cancel{\textcolor{b l a c k}{44}}} 4 \text{ cents}}{\textcolor{red}{\cancel{\textcolor{b l a c k}{11}}}} = c$

$28 \times 4 \text{ cents} = c$

$112 = c$

$c = 112$

28 inches of wire will cost 112 cents.