Suppose that A is an acute angle and cosA=4/5. Find the exact value of sinA/2 ?
1 Answer
Apr 26, 2018
Explanation:
#"using the "color(blue)"half angle formula"#
#•color(white)(x)sin(A/2)=+-sqrt((1-cosA)/2)#
#"since A is an acute angle then "sin(A/2)>0#
#sin(A/2)=+sqrt((1-4/5)/2)+sqrt((1/5)/2)=+sqrt(1/10)#
#color(white)(xxxxxx)=1/sqrt10=sqrt10/10#