Systems of equations help?

-10x-20y=-20
-5x-10y=10

With work (please!)

1 Answer
May 14, 2018

The systems of equns.has no solution.to phi

Explanation:

Here,

-10x-20y=-20

Dividing each term by (-10) ,we get

color(red)(x+2y=2...to(1)

Also given that,

-5x-10y=10

Dividing each term by (-5) ,we get

color(red)(x+2y=-2...to(2)

Subtracting equn.(1) from (2)

x+2y=2

x+2y=-2

ul(- -color(white)(.........)+

color(white)(..............)0=4 to which is false statement.

Thus, the pair of equn. has no solution.

Let us draw the graphs of equn. (1) and(2)

From the graph ,we can say that the lines are parallel.

i.e.two lines donot intersect anywhere.

So, the systems of equns.has no solution.

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Note:
We know that :If for a_1,b_1,c_1,a_2,b_2,c_2 in RR

a_1x+b_1y+c_1=0 , where,a_1^2+b_1^2!=0

a_2x+b_2y+c_2=0 , where,a_2^2+b_2^2!=0 and

and a_1/a_2=b_1/b_2!=c_1/c_2=>No color(white)(.)Solution.

In short, 1/1=2/2!=2/(-2) to phi