The acceleration of a bus is given by a-at, where a= 1.5 m/s^2...?

Question

The acceleration of a bus is given by a-at, where a= 1.5 m/s^2.

If bus's velocity at time t=1.0 s is 5.0 m/s, what is it's velocity at time t=2.0 s? If the bus's position at time t=1.0 s is 6.0m, what is it's position at time t=2.0 s?

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Answer 1 · 2018-07-15T09:50:01

Please see the explanation below

The acceleration is #a=1.5ms^-2#

The velocity #u_1=5.0ms^-1# at #t=1s#

Apply the equation of motion

#v=u+at#

#v=u_1+a(t_2-t_1)#

#=5+1.5*(2-1)#

#=6.5ms^-1#

The velocity at #t=2.0s# is #v_2=6.5ms^-1#

The position is #s_1=6.0m#

Apply the equation of motion

#s_2-s_1=1/2(v_2+v_1)(t_2-t_1)#

Therefore,

#s_2-6=1/2(11.5*1)#

#s_2=6+5.75=11.75m#

The position at time #t=2s# is #=11.75m#