# The acceleration of a particle traveling along a straight line is a = (8-2s) m/s^s, where s is in meters. How do you determine the position of the particle when the velocity is maximum?

May 20, 2016

I got at $4 m$

#### Explanation:

I would use Algebra and Kinematics here :
I know that acceleration is the derivative of velocity BUT also that if I want the maximum of a function I need to derive it and set the derivative equal to zero;
here I have the derivative of velocity (acceleration) so I set it equal to zero to get:
$8 - 2 s = 0$
$s = \frac{8}{2} = 4 m$

Does it make sense?