The acceleration of gravity in the moon is 1.6 m/s^2 . If a ball is dropped on a height of 2.57 m, determine the time for the ball to fall to the surface of the moon. ?
1 Answer
Jul 12, 2018
Assuming that the ball is dropped with zero initial velocity
#h=ut+1/2at^2#
where#h# is height#a# acceleration and#t# time taken to reach surface of the moon.,
Inserting given vales in the expression we get
#2.57=0xxt+1/2(1.6)t^2#
#=>t=sqrt(2.57xx2/1.6)#
#=>t=+-1.8\ s#
Ignoring negative root as time can not be negative we obtain
#=>t=1.8\ s#
