The area of a rectangle is $20x^2-27x-8$ . The length is $4x+1$ . What is the width?

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Answer 1 · 2017-03-13T07:38:40

The width is $=(5x-8)$

The area of a rectangle is

$A=L * W$

$A=20x^2-27x-8$

$L=4x+1$

$W=A/L=(20x^2-27x-8)/(4x+1)$

We perform a long division

$color(white)(aaaa)$ $20x^2-27x-8$ $color(white)(aaaa)$ $|$ $4x+1$

$color(white)(aaaa)$ $20x^2+5x$ $color(white)(aaaaaaaaa)$ $|$ $5x-8$

$color(white)(aaaaaaa)$ $0-32x-8$

$color(white)(aaaaaaaaa)$ $-32x-8$

$color(white)(aaaaaaaaaaa)$ $-0-0$

Therefore,

$W=5x-8$

The area of a rectangle is 20x^2-27x-820x^2-27x-8. The length is 4x+14x+1. What is the width?