# The average cup of coffee contains about 11.0 moles of water. What would this mass of water be?

It is $18.01 \cdot g \cdot m o {l}^{-} 1$... How did I know this? How will you get this?
And so if we gots $11 \cdot m o l$ of water....to get the mass we take the product...
$11 \cdot m o l \times 18.01 \cdot g \cdot m o {l}^{-} 1 \cong 200 \cdot g \cong 200 \cdot m L$