Question

The average molecular speed in a sample of CO2 gas at a certain temperature is 384 m/s. The average molecular speed in a sample of H2gas is m/s at the same temperature. ?

Answer 1

`"1801 m/s"`

Explanation:

Average speed of molecule is given as

`bar v = sqrt((8RT)/(π M)`

From above relation `bar v prop 1/sqrt(M)`

So,

`(barv_("CO"_2))/(barv_("H"_2)) = sqrt((M_("H"_2))/(M_("CO"_2)))`

`("384 m/s")/barv_("H"_2) = sqrt("2 g/mol"/"44 g/mol") = 1/sqrt(22)`

`barv_("H"_2) = "384 m/s" × sqrt(22) = "1801 m/s"`