Question

The barometric pressure on Pike's Peak, altitude 4,302 m above sea level, is 442 mm Hg. How would you calculate this pressure in atmospheres (atm) and psi (Ib/`i n^2`)?

Answer 1

Well, we know that `1*atm` will support a column of mercury that is `760*mm*Hg` high.....

Explanation:

And thus `760*mm*Hg-=1*atm`.

And so `(446*mm*Hg)/(760*mm*Hg*atm^-1)=0.587*atm`. And what is this in `lb*"in"^2`?