# The barometric pressure on Pike's Peak, altitude 4,302 m above sea level, is 442 mm Hg. How would you calculate this pressure in atmospheres (atm) and psi (Ib/i n^2)?

Well, we know that $1 \cdot a t m$ will support a column of mercury that is $760 \cdot m m \cdot H g$ high.....
And thus $760 \cdot m m \cdot H g \equiv 1 \cdot a t m$.
And so $\frac{446 \cdot m m \cdot H g}{760 \cdot m m \cdot H g \cdot a t {m}^{-} 1} = 0.587 \cdot a t m$. And what is this in $l b \cdot {\text{in}}^{2}$?