The cable supporting a 2100-kg elevator has a maximum strength of 21750N. What maximum upward acceleration can it give the elevator without breaking?

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Answer 1 · 2018-06-13T00:26:53

I get #~~10.36 \ "m/s"^2#.

We use Newton's second law of motion here, which states that,

#F=ma#

where:

#F# is the force applied in newtons

#m# is the mass of the object in kilograms

#a# is the acceleration of the object in meters per second squared

So we get:

#a=F/m#

#=(21750 \ "N")/(2100 \ "kg")#

#~~10.36 \ "m/s"^2#