The coordinates of point P are (-2,3) and the gradient of the straight line PQ is 3. Find the coordinates of Q?

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Answer 1 · 2015-10-09T16:47:30

#Q=(-2+r, 3+3r)#

There is insufficient data to locate a unique coordinate location for #Q#

The best I have been able to do is express it in terms of a variable #r#

Answer 2 · 2015-10-09T16:51:10

There are infinitely many Q that will work.

Point #P# is #(-2,3)#

Let #Q# be #(x,y)#.

Given #(Delta y) / (Deltax) = 3#, we need to solve

#(y-3)/(x+2)=3#

Any (and every) point on the line #y=3x+9# will meet the requirements.