The energy of an electron in 1st bohr orbit of H atom is -13.6 eV. The possible energy value of electron in excited state of doubly ionised Lithium is what?

Question

13683 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-20T23:34:43

#-122.4/("n"+ 1)^2\ "eV"#,

#"n" = 1, 2, 3, . . . #

Energy of an electron in hydrogen like species in #"n"^"th"# shell is given by

#"E" = -13.6\ "Z"^2/"n"^2\ "eV"#

For electron in first orbit of #""_3^7"Li"^(2+)#

#"E"_1 = -13.6 xx 3^2/1^2\ "eV" = -122.4\ "eV"#

For electron in second orbit (#"1st"# excited state) of #""_3^7"Li"^(2+)#

#"E"_2 = -13.6 xx 3^2/2^2 = -30.6\ "eV"#

Energy of electron in an orbit after #"n"^"th"# excited state

#"E"_"ne" = -13.6 × 3^2/("n" + 1)^2\ "eV" = -122.4/("n" + 1)^2\ "eV"#