The energy required to remove an electron from sodium is #8.23x10^-19#J. At what frequency of light will sodium ionize?

1 Answer
anor277
Sep 22, 2016

#E=hnu#, #nu=E/h=(8.23xx10^-19*J)/(6.626xx10^-34*J*s)# #=# #??s^-1#

Explanation:

We use the #"Planck relationship, "E=hnu#, where #h="Planck's constant,"# #6.626xx10^-34*J*s#.

Given #E=hnu#, #nu=E/h=(8.23xx10^-19*J)/(6.626xx10^-34*J*s)# #=# #??s^-1#.

Clearly we get an answer in #s^-1#, as is required for a frequency.

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