The equation for the combustion of glucose is: C6H12O6(s) + 6O2(g) --> 6CO2(g) + 6H2O(g). How many grams of H2O will be produced when 8.064g of glucose is burned?

1 Answer
Nov 23, 2015

Answer:

Between 0.5 and 1.0 g of water.

Explanation:

#C_6H_12O_6(s) + 6O_2(g) rarr 6CO_2(g) + 6H_2O(g)#

Moles of glucose, #=# #(8.064*cancel(g))/(180.16*cancel(g)*mol^-1)# #=# #4.476xx10^-2# #mol#.

From the equation above, there will be approximately 0.8 g water produced.