The equation of tangent to the circle x^2+y^2=r^2 is y=mx+c ,then the point of contact of the circle and the tangent is?
The point of contact can be found by equating the equations together. This will find a value that is common to both equations and consequently will be the point or points of contact.
So we have
Point of contact:
Let, the Line
From Geometry, we know that, in a circle, the
the centre to a tgt. equals the radius.
Recall that, the
Utilising these facts, we have,
Hence, the tgt.
To find the eqn. of
its slope is
Therefore, the pt. of contact is,