The equation of the trajectory of particle is #x=sqrt3 y-5y^2#.The particle is at t=0 at origin.Its acceleration is #veca=-10 hati#.What is its initial velocity?
1 Answer
Here given acceleration is
Let the velocity of projection of the particle from the origin (0,0) be
So resolved components are
Let the particle takes time
So
and
Combining [1] and[2] we get
So we obtain this equation of trajectory.
Again the given equation of trajectory is
Comparing [3] and [4] we get
and
So
Hence initial velocity