# The equation #P = 1 + d/33# gives the pressure, #P#, in atmospheres (atm) at a depth of #d# feet below sea level. For what depths #d# is the pressure at least 1 atm and at most 2 atm?

##### 1 Answer

#### Explanation:

For starters, you can find the value of *definition* of an **atmosphere**.

As you know, the **atmosphere** is a unit of pressure defined as the pressure exerted by the Earth's atmosphere **at sea level**.

Since at sea level basically means a depth of **feet**, you can say that the first value of

#d = "0 feet"#

Now, you know that you must have

#P_1 = 1 + d_1/33 >= "1 atm"#

The depth#d_1# corresponds to a pressure of at least#"1 atm"#

and also

#P_2 = 1 + d_2/33 <= "2 atm"#

The depth#d_2# corresponds to a pressure of at most#"2 atm"#

From the first inequality, you get that

#1 + d_1/33 = 1#

#d_1/33 = 0 implies d_1 = "0 feet" -># matches what we got by using thedefinitionof an atmosphere!

For the second inequality, you get that

#1 + d_2/33 <= 2#

#d_2/33 <= 1 implies d_2 <= "33 feet"#

Therefore, you can say that the pressure is at least

Notice that you can also set up this as a *compound inequality*

#1 <= 1 + d/33 <= 2#

Solve this to get

#0 <= d/33 <= 1#

#o<= d <= 33#

Once again, you get