# The FCS #tan_(fcs)(pix: pi) = tan (pix+ pi (tan (pix + pi tan (pix +...)#. How do you graph this FCS to reveal x-intercepts #0, +-1, +_2, +3|-...#?

##### 1 Answer

Jun 30, 2018

See graph and explanation.

#### Explanation:

As #y = tan_(fcs)( pix; pi ) = tan ( pi ( x + y ) ), inversely,

So, upon setting

See graph for these x-intercepts.

graph{y - tan ( pi ( x + y )) = 0[-10 10 -2 2] }