The following are some enthalpy values for reactions between nitrogen and oxygen: N2(g) + O2(g) → 2NO(g) ∆H = 180.4 kJ mol−1 N2(g) + 2O2(g) → 2NO2(g) ∆H = 66.4 kJ mol−1 Use these values to calculate ∆H for the reaction: NO(g) + ½O2(g) → NO2(g)?
1 Answer
May 16, 2018
I make it....
Explanation:
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We want...
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...which is PRECISELY the expression whose enthalpy change we want to evaluate...
And so...