The function 2x^2=12x+y-22 has a critical point where x = and y = help!?

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Answer 1 · 2017-08-05T06:05:05

The critical point is #=(3,4)#

Let's rewrite the equation

#2x^2=12x+y-22#

#y=2x^2-12x+22#

Calculate the first derivative

#dy/dx=4x-12#

The critical point is when

#dy/dx=0#

#4x-12=0#

#x=12/4=3#

and

#y=4#

The function 2x^2=12x+y-22 has a critical point where x = ____ and y = ____ help!?