Question

The general solution of the equation 2sin x+1=0 is?

Answer 1

In radians: `x=-pi/6+ 2pin` or `x=-(5pi)/6 +2pin`, `n∈Z`

Explanation:

`2sinx + 1= 0`

`2sinx = -1`

`sinx = -1/2`

`x =sin^-1(-1/2) = -pi/6` or `-(5pi)/6`

General solution: `x=-pi/6+ 2pin` or `x=-(5pi)/6 +2pin`, `n∈Z`