The general solution of the equation 2sin x+1=0 is?

1 Answer
Mar 8, 2018

In radians: #x=-pi/6+ 2pin# or #x=-(5pi)/6 +2pin#, #n∈Z#

Explanation:

#2sinx + 1= 0#

#2sinx = -1#

#sinx = -1/2#

#x =sin^-1(-1/2) = -pi/6# or #-(5pi)/6#

General solution: #x=-pi/6+ 2pin# or #x=-(5pi)/6 +2pin#, #n∈Z#