The heat of vaporization of alcohol is 879 #Jg^-1#. What is the energy (in J) required to vaporize #4.50# #g# of alcohol, #C_2H_5OH#?

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Answer 1 · 2017-05-21T22:32:40

#879# joules per gram times #4.50# grams equals #3955.5# joules

This is a fairly straightforward question. Each gram of alcohol requires #879# #J# to vaporise it, and there are #4.5# #g#, so we simply multiply.

Notice the units: #Jg^-1*g = J#