# The heat of vaporization of water is 2260 J/g. How do you calculate the molar heat of vaporization (J/mol) of water?

##### 1 Answer
Aug 31, 2017

Well multiply the heat of vaporiziation by the molar mass to get the molar quantity.....

#### Explanation:

We assess.......

${H}_{2} O \left(l\right) + \Delta \rightarrow {H}_{2} O \left(g\right)$

And thus $\text{per mole, i.e.}$ $m o {l}^{-} 1$, we gots, $2260 \cdot J \cdot {g}^{-} 1 \times 18.01 \cdot g \cdot m o {l}^{-} 1$

$40.7 \cdot k J \cdot m o {l}^{-} 1$.........and note that the positive charge represents the heat that must be put into the system......