The heat of vaporization of water is 2260 J/g. How do you calculate the molar heat of vaporization (J/mol) of water?

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Answer 1 · 2017-08-31T07:53:55

Well multiply the heat of vaporiziation by the molar mass to get the molar quantity.....

We assess.......

#H_2O(l) +DeltararrH_2O(g)#

And thus #"per mole, i.e."# #mol^-1#, we gots, #2260*J*g^-1xx18.01*g*mol^-1#

#40.7*kJ*mol^-1#.........and note that the positive charge represents the heat that must be put into the system......