Question

The integral of(4x^3 -12x)(x^4 -6x^2)^3 dx?

Answer 1

`-(x^4-6x^2)^(-2)/2+C`

Explanation:

After using `u=x^4-6x^2` and `du=(4x^3-12x)*dx` transforms, this integral became

`int (du)/u^3`

=`int u^(-3)*du`

=`u^(-2)/(-2)+C`

=`-(x^4-6x^2)^(-2)/2+C`