# The latent heat of vaporization of water is 2260 J/g. How many grams of water at 100°C can be converted to steam by 226,000 J of energy?

Feb 1, 2015

The answer is: $m = 100 g$.

To answer to this question it is sufficient to use this equation:

$Q = L m$

where

$Q$ is the amount of heat needed to convert water in steam;

$L$ is the latent heat of vaporization of water;

$m$ is the mass of the water.

So:

$m = \frac{Q}{L} = \frac{226000 J}{2260 \frac{J}{g}} = 100 g$.