The legs of an isoseles triangle are equal to 25 inches each. if the altitude to the base is 7 inches long, find the area of the triangle?

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Answer 1 · 2018-05-23T11:20:40

Area = 168 square inches

The altitude bisects the base, using Pythagoras

#25^2-7^2=(1/2b)^2#

#625-49=(1/2b)^2#

#(1/2b)=sqrt576#

#(1/2b)=24#

#b=48#

Area= #1/2xx48xx7#

Area=168