If any doubt and the question lends itself to it draw a little sketch. This helps in understanding what to do. Does not need to all neat and fancy like mine. A very quick and rough sketch will do.
#"area " ="length "xx" width" color(magenta)( larr" Important to remember this")#
#color(white)("d")1/2color(white)("dd")= color(white)("d")2/3color(white)("dd.d")xx color(white)("dd")wcolor(white)("dd") larr " Given in the question"#
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#color(blue)("Determine the value of "w)#
#color(green)(1/2=2/3w)#
This is the same as:
#color(green)(1/2=2xx1/3xxw)#
Multiply both sides by #color(red)(1/2)#
#color(green)(ubrace(1/2color(red)(xx1/2))=ubrace(2color(red)(xx1/2))xx1/3xxw)#
#color(green)(color(white)("dd")1/4color(white)("dd")=color(white)("d..")ubrace(2/color(red)(2)color(white)("dd")xx1/3)xxw)#
#color(green)(color(white)("dd")1/4color(white)("dd")=color(white)("ddddd")1/3color(white)("ddd")xxw)#
Multiply both sides by #color(red)(3)#
#color(green)( color(red)(3)/4 = ubrace(color(red)(3)/3xx w)#
#color(green)(3/4 = color(white)("dd")w )#
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#color(blue)("Determine the area")#
#"area = length x width"#
#color(white)("d")a= 2/3xx3/4color(white)("dd") =color(white)("dd") (2xx3)/(3xx4) color(white)("dd")=color(white)("dd")6/12#
#a = (6-:6)/(12-:6)color(white)("dd") =color(white)("dd") 1/2 # square mile