The length of a rectangle is 4cm more than the width and perimeter is at least 48cm. What are the smallest possible dimensions for the rectangle?

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Answer 1 · 2015-06-22T00:31:21

Let's call the width of the rectangle #x#, then the length #=x+4#

The perimeter #p# will then be:
2x length + 2x width:
#p=2*(x+4)+2*x=4x+8#

The smallest possible dimensions are when #p=48#:

#4x+8=48->4x=40->x=10#

Answer : #14" x "10cm#