# The length of a rectangle is 4cm more than the width and perimeter is at least 48cm. What are the smallest possible dimensions for the rectangle?

Jun 22, 2015

Let's call the width of the rectangle $x$, then the length $= x + 4$

#### Explanation:

The perimeter $p$ will then be:
2x length + 2x width:
$p = 2 \cdot \left(x + 4\right) + 2 \cdot x = 4 x + 8$

The smallest possible dimensions are when $p = 48$:

$4 x + 8 = 48 \to 4 x = 40 \to x = 10$

Answer : $14 \text{ x } 10 c m$