The length of a rectangle is three times its width. The perimeter is at most 112 centimeters What is the greatest possible value for the width?

Nov 30, 2016

So maximum width is 14cm

Explanation:

Let length be $L$
Let width be $w$

Given that $L = 3 w$

Given that perimeter max is 112 cm $\implies 2 L + 2 w = 112$

As $L = 3 w \text{ then "2L+2w=112" "->" } 2 \left(3 w\right) + 2 w = 112$

$\implies 8 w = 112$

$w = \frac{112}{8} = 14$