Question

The length of rectangle is twice its breadth. If its perimeter is 48 cm, find the dimensions of the rectangle?

Answer 1

The breadth [height] is 8 and the length [base] is 16

Explanation:

It's always helpful to put rewrite questions into equations, so that they are easier to solve.

When we see: The length [base] of the rectangle is twice its breadth [height].
We can write: `b = 2h`

Now do the second part. Remember that the perimeter is the distance around the figure (as if you were putting down a fence) so it is the length of all it's sides added together. For this rectangle it is `b+h+b+h` or `2b + 2h`

When we see: It's perimeter is 48
We can write: `2b +2h = 48`

Let's combine the two equations to find our answers. Let's substitute the first equation into the second one.
Since `b = 2h` we can also say

`2b +2h = 48`

`2(2h) +2h = 48`

`4h + 2h = 48`

`6h = 48`

`(cancel(6)h)/cancel(6 )= 48/6`

`h = 8`

Now that we know `h`, we can plug that into the first equation.
`b = 2h`
`b = 2(8)`
`b = 16`