# The mass of a block of metal (11:5+-0.5)kg and its volume is (1000+-20)cm3 how would you express the density of the metal?

Mar 27, 2018

$D e n s i t y = 0.0112 \frac{k g}{c {m}^{3}}$
or
$D e n s i t y = 1.12 \cdot {10}^{-} 2 \frac{k g}{c {m}^{3}}$

#### Explanation:

$D e n s i t y = \frac{m a s s}{v o l u m e}$

$M a s s = 11.5 + \left(- 0.5\right)$
$M a s s = 11 k g$

$V o l u m e = 1000 + \left(- 20\right)$
$V o l u m e = 980 c {m}^{3}$

$D e n s i t y = \frac{11 k g}{980 c {m}^{3}}$

$D e n s i t y = 0.0112 \frac{k g}{c {m}^{3}}$
or
$D e n s i t y = 1.12 \cdot {10}^{-} 2 \frac{k g}{c {m}^{3}}$