The mass of each car is 600kg, 970kg, 230kg, 810kg, 660kg. The force of friction on each car is 1980N, 3201N, 759N, 2673N, 2178N respectively. What is the magnitude of the upward forces on the 5th car?
2 Answers
If car is on horizontal road then upward normal reaction R on the car is equal to its weight
So
Again
So for Car 1
So for Car 2
So for Car3
So for Car 4
So for Car 5
So for every car Upward reaction
Hence for 5th car
We know that Normal reaction
Also that force of friction is given as
where
Assuming that all cars are located on the same plane and have same coefficient of friction.
For car
Inserting given values we get
Similarly for car
Similarly for car
Similarly for car
We see that value of
Even though it has been not stated in the problem, it is assumed that all cars are in a state of equilibrium while resting on the plane. As such
For car
from (1) we have