The mean number of seeds in a watermelon is 176 and the standard deviation is 40. What percentage of melons have between 150 and 200 seeds?

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Answer 1 · 2017-03-21T05:36:07

Percentage of watermelons have seeds between 150 and 200 $46.79%$

Given -

Mean $barx=176$
SD $sigma = 40$

At $x=150$

$z=(x-barx)/sigma= (150-176)/40=-0.65$

At $x=200$

$z=(x-barx)/sigma= (200-176)/40=-0.6$

Probability $x$ takes a value between 150 and 200 = [Area between $z=-0.65$ and $z=0$ ]+ [Area between $z=0$ and $z=0.6$ ]

$=0.2422+0.2257=0.4679$

Percentage of watermelons have seeds between 150 and 200 $=0.4679 xx 100=46.79%$

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