Question

The mean number of seeds in a watermelon is 176 and the standard deviation is 40. What percentage of melons have between 150 and 200 seeds?

Answer 1

Percentage of watermelons have seeds between 150 and 200 `46.79%`

Explanation:

Given -

Mean `barx=176`
SD `sigma = 40`

At `x=150`

`z=(x-barx)/sigma= (150-176)/40=-0.65`

At `x=200`

`z=(x-barx)/sigma= (200-176)/40=-0.6`

Probability `x` takes a value between 150 and 200 = [Area between `z=-0.65` and `z=0`]+ [Area between `z=0` and `z=0.6`]

`=0.2422+0.2257=0.4679`

Percentage of watermelons have seeds between 150 and 200 `=0.4679 xx 100=46.79%`