Question

The partial pressures of the gases in a miture are 0.00461 atm `O_2`, 1.78 atm `N_2`, and 0.975 atm `Ar`. What is the total pressure of the mixture?

Answer 1

The total pressure is simply the sum of the individual partial pressures..........

Explanation:

`P_"Total"=P_(O_2)+P_(N_2)+ P_(Ar)`

`=(4.61xx10^-2 + 1.78+0.975)*atm`

`~=2.76*atm`

This is a simple result of `"Dalton's Law of Partial Pressure"`, for which see here.