The perimeter of a local dog 156 feet. If the length of the park is 2 feet less than 3 times the width, what are the dimensions of the dog park?
1 Answer
Dec 7, 2016
Total area is 1160 sq. feet. Length is 58 feet and width is 20 feet.
Total area is 58*20=1160
Explanation:
Since we know that length is 2 less than 3 times of width
and we know that perimeter is [P]
So length is
L= 3W-2
P= 2L + 2W [ that is 2xLength + 2x Width]
156 = 2( 3W-2) + 2 W
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Hence answer is length is 20 Feet.
Now we can find out the length of park:
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Hence Length is 58 feet
Now again we can verify the answer by determine the perimeter
Since P = 2L+2W
Hence
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