The perimeter of a regular hexagon is 48 inches. What is the number of square inches in the positive difference between the areas of the circumscribed and the inscribed circles of the hexagon? Express your answer in terms of pi.

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The perimeter of a regular hexagon is 48 inches. What is the number of square inches in the positive difference between the areas of the circumscribed and the inscribed circles of the hexagon? Express your answer in terms of pi.

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Answer 1 · 2018-08-05T02:15:19

$Diff. in area between Circumscribed and Inscribed circles$ $color(blue)("Diff. in area between Circumscribed and Inscribed circles "$

$A_{d} = π R^{2} - π r^{2} = 36 π - 27 π = 9 π sq inch$ $color(green)(A_d = pi R^2 - pi r^2 = 36 pi - 27 pi = 9pi " sq inch"$

Explanation:

Perimeter of regular hexagon $P = 48 inch$ $P = 48 "inch"$

Side of hexagon $a = \frac{P}{6} = \frac{48}{6} = 6 inch$ $a = P / 6 = 48 / 6 = 6 " inch"$

Regular hexagon consists of 6 equilateral triangles of side a each.

![http://www.oocities.org/web_sketches/calculators/regular_polygon/regular_polygon_layout.html]( useruploads.socratic.org )

Inscribed circle : Radius $r = \frac{a}{2 tan θ}, θ = \frac{60}{2} = 30^{\circ}$ $r = a / (2 tan theta), theta = 60/2 = 30^@$

$r = \frac{6}{2 tan (30)} = \frac{6}{2 (\frac{1}{\sqrt{3}})} = 3 \sqrt{3} inch$ $r = 6 / (2 tan (30)) = 6 / (2 (1/sqrt3)) = 3 sqrt 3 " inch"$

$Area of inscribed circle A_{r} = π r^{2} = π {(3 \sqrt{3})}^{2} = 27 π sq inch$ $"Area of inscribed circle " A_r = pi r^2 = pi (3 sqrt3)^2 = 27 pi " sq inch"$

![http://davechessgames.blogspot.com/2011/01/mathematical-problems-3dhttp://-pi-from.html](https://useruploads.socratic.org/C10luMItRGi1ydPSkEqa_inscribed%20hexagon.jpg)

$Radius of circumscribed circle R = a = 6 inch$ $"Radius of circumscribed circle " R = a = 6 " inch"$

$Area of circumscribed circle A_{R} = π R^{2} = π 6^{2} = 36 π sq inch$ $"Area of circumscribed circle "A_R = pi R^2 = pi 6^2 = 36 pi " sq inch"$

$Diff. in area between Circumscribed and Inscribed circles$ $"Diff. in area between Circumscribed and Inscribed circles "$

$A_{d} = π R^{2} - π r^{2} = 36 π - 27 π = 9 π sq inch$ $A_d = pi R^2 - pi r^2 = 36 pi - 27 pi = 9pi " sq inch"$

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The perimeter of a regular hexagon is 48 inches. What is the number of square inches in the positive difference between the areas of the circumscribed and the inscribed circles of the hexagon? Express your answer in terms of pi.

1 Answer

Explanation:

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