The perimeter of a triangle is 51 cm. The lengths of its sides are consecutive odd integers. How do you find the lengths?

May 16, 2018

16, 17 and 18

Explanation:

$a + b + c = 51$
$a + a + 1 + a + 2 = 51$
$3 a = 48$
$a = 16$
$b = 17$
$c = 18$

May 16, 2018

The sides are $15 c m , 17 c m \mathmr{and} 19 c m$

Explanation:

Let the shortest side be $x$.

If the sides are consecutive odd integers, the other two sides will be $\left(x + 2\right) \mathmr{and} \left(x + 4\right)$

The perimeter is the sum of the sides.

$x + x + 2 + x + 4 = 51$

$3 x + 6 = 51$

$3 x = 51 - 6$

$3 x = 45$

$x = 15$

The length of the shortest side.

The other sides are $17 c m \mathmr{and} 19 c m$