# The point (2k-8,10)lies on the Y axis.find the value of k?

Apr 6, 2018

k = 4

#### Explanation:

This problem gives you some extraneous (extra) information in an attempt to trick you.

If the point lies on the y-axis then the $x$ value of the point must be zero. Consider that any point on the y-axis has the form (0, $n$), where $n$ is some number.

Since our point can be written as $\left(0 , n\right)$, it follows that $\left(0 , n\right) = \left(2 k - 8 , 10\right)$. So $0 = 2 k - 8$ and $n = 10$. We are only interested in the value of $k$. The algebra, at this point, is:

$0 = 2 k - 8$
$8 = 2 k$
$4 = k$

And we have our answer: $k = 4$.

Apr 6, 2018

$k = 4$

#### Explanation:

The point $\left(2 k - 8 , 10\right)$ can only lie on the $y$-axis when the $x$ coordinate is $0$.

Therefore, $2 k - 8 = 0 \implies k = 4$