The population of Grand City in 1990 was 5,250. Assume the population is increasing at 2.5% per year. What was the population in Grand City in 2010 (round answer to the nearest person)?

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I don't know how to put the question together. Like do I multiply? Divide?

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Answer 1 · 2018-05-07T03:27:07

#"Population" = 7744#

Using the number of terms arithmetic progression..

#T_n= a+(n-1)d#

Where;

#a=5250#

#n = 2010-1990=20#

#d = 2.5%# of #5250 = 131.25#

#T_20 = 5250 + (19)131.25#

#T_20= 7744#