The position of an object moving along a line is given by p(t) = cos(t- pi /3) +2 p(t)=cos(tπ3)+2. What is the speed of the object at t = (2pi) /4 t=2π4?

1 Answer
Apr 24, 2017

0.5 units/s

Explanation:

v(t) =(dp)/(dt) =d/(dt) cos(t-pi/3)+2 =-sin(t-pi/3)v(t)=dpdt=ddtcos(tπ3)+2=sin(tπ3)

At t=(2pi)/4t=2π4,
v(t) = -sin((2pi)/4-pi/3)= -sin(pi/6)= -0.5v(t)=sin(2π4π3)=sin(π6)=0.5