# The position of an object moving along a line is given by p(t) = t^2 - 2t +3. What is the speed of the object at t = 1 ?

May 24, 2016

$\text{the speed of the object at t=1 is zero.}$

#### Explanation:

$v \left(t\right) = \frac{d}{d t} p \left(t\right)$

$v \left(t\right) = \frac{d}{d t} \left({t}^{2} - 2 t + 3\right)$

$v \left(t\right) = 2 t - 2 + 0$

$v \left(1\right) = 2 \cdot 1 - 2$

$v \left(1\right) = 2 - 2$

$v \left(1\right) = 0$