The potential energy of a particle varies with distance as U= (Asqrt(x))/(x^2 + B), where A and B are constants. The dimensional formula for A * B is?

1 Answer
Jan 14, 2018

Dimension of A is equals to dimension of {U(x^2+B)}/sqrtx or [M L^2 T^-2].[L^2]/[L^(1/2)] i.e [M L^(7/2) T^-2]

And dimension of B is equals square of x that is [L^2] (because two quantities can be added only when their dimension is the same)

So dimension of A.B will be [M L^(11/2) T^-2]