Question

The pressure of a gas at 35.60C is 114.3kPa. What is the pressure when the temperature drops to 17.3 0C? Assume constant volume?

Answer 1

Approximately `55.5` kilopascals.

Explanation:

At constant volume, we can use Gay-Lussac's Law, which states that,

`PpropT` or `P_1/T_1=P_2/T_2`

So, we get:

`(114.3 \ "kPa")/(35.6^@"C")=P_2/(17.3^@"C")`

`P_2=(114.3 \ "kPa")/(35.6color(red)cancelcolor(black)(""^@"C"))*17.3color(red)cancelcolor(black)(""^@"C")`

`~~55.5 \ "kPa"`